In a Triangle ABC, D, E, F are respectively, the midpoints of BC,CA and AB. If the lengths of sides AB, BC and CA are 17cm , 28 cm and 19 cm. find the perimeter of Triangle DEF.
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Question:- Find perimeter of ∆DEF
Given:-
D,E,F are the midpoints of BC,CA and AB respectively
AB=17 cm
BC=28 cm
CA=19 cm
Solution:-
F is the midpoint of AB
thus
AF+BF=AB=17 cm
AF=BF=17/2=8.5
also
D is the midpoint of BC
then
BD+DC=BD=28
BC=BD=14
In ∆FBD
FB=8.5 BD=14 DF=?
also
E is the midpoint of AC
that is
AE+EC=AC=19
AE=EC=19/2=9.5
also DC=14 (already found)
In ∆DEC
DC=14 CE=9.5 DE=?
Also
FA=8.5 EA=9.5 EF=?
We've to take the half of all given angles for finding the answer
that is
9.5+8.5+14
=18+14
=32
therefore the perimeter of ∆DEF is 32cm
Hope it helps
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