Math, asked by gamingcrown743, 14 days ago

In a triangle ABC, ‘D’ is a point on AB and ‘E’ is a point on AC such that DE is parallel to BC. If AD = 2cm, DB = 3cm, AE = 1.2cm, then find the value of EC.

Answers

Answered by vinkamble2015
1

Answer:

EC = 1.8

Step-by-step explanation:

For Tri. ABC

By BPT Theorem : If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points then the other two sides are divided in the same ratio.

AD/DB = AE/EC

2/3 = 1.2/EC

EC = (1.2 x 3)/2 = 1.8

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