In a triangle ABC, ‘D’ is a point on AB and ‘E’ is a point on AC such that DE is parallel to BC. If AD = 2cm, DB = 3cm, AE = 1.2cm, then find the value of EC.
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Answer:
EC = 1.8
Step-by-step explanation:
For Tri. ABC
By BPT Theorem : If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points then the other two sides are divided in the same ratio.
AD/DB = AE/EC
2/3 = 1.2/EC
EC = (1.2 x 3)/2 = 1.8
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