In a triangle ABC,D is a point on side BC such that angle ADC = Angle BAC. if CA = 12cm and CB =8Cm ,then CD is equal to??
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The answer to the question is 18 cm.
Which means,CD=18cm
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Given: Angle BAC= Angle ADC
Find: CD
Proof: ∆ BAC~ ∆ ADC (AA similarity)
as Angle BAC= Angle ADC
and angle C is common
Therefore, AC/DC= BC/AC (by CPST)
By solving this we get CD= 18 cm
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