Question

 In a triangle ABC , DE is parallel to BC. If AE= 3cm, EC = 4cm, DB = 6cm , then AD is equal to *

1 point

7.5cm

3cm

4.5cm

6cm​

Answer 1

Step-by-step explanation:

$In \: \triangle \: ABC and \: \triangle \: ADE$

$\frac{AE }{EC} = \frac{AD }{DB} \: \: \: \: \: \: \: \: (by \: thales \: theorem)$

$\frac{3}{4} = \frac{AD}{6}$

$AD = \frac{18}{4}$

$\boxed{AD = 4.5}$

Hence option c. is correct one