In a triangle ABC , E and F are the mid points of AC and AB respectively . The altitude AP to BC intersect EF at Q .Provet that AQ = QP.
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Answered by
144
Hey,
In triangle ABC,
F is the mid point of AB
E is the mid point of AC
Therefore,
FE//AB & FE=1/2AB(Mid point theorem).
Now,
In triangle ABP,
F is the mid point of AB
FQ//BP(FQ and BP are parts of FE and BC respectively)
Therefore,
Q is the mid point of AP(Converse of mid point theorem)
Hence, AQ=QP.
Hence, proved.
Hope this helps you!!!!
In triangle ABC,
F is the mid point of AB
E is the mid point of AC
Therefore,
FE//AB & FE=1/2AB(Mid point theorem).
Now,
In triangle ABP,
F is the mid point of AB
FQ//BP(FQ and BP are parts of FE and BC respectively)
Therefore,
Q is the mid point of AP(Converse of mid point theorem)
Hence, AQ=QP.
Hence, proved.
Hope this helps you!!!!
Answered by
14
Answer:
In triangle ABC,
F is the mid point of AB
E is the mid point of AC
Therefore,
FE//AB & FE=1/2AB(Mid point theorem).
Now,
In triangle ABP,
F is the mid point of AB
FQ//BP(FQ and BP are parts of FE and BC respectively)
Therefore,
Q is the mid point of AP(Converse of mid point theorem)
Hence, AQ=QP.
Hence, proved.
Read more on Brainly.in - https://brainly.in/question/2606191#readmoretep-by-step explanation:
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