In a triangle ABC, if 2∠A=3∠B=6∠C, calculate the measure of ∠B.
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Answered by
59
this will be ur ans u see the process and I will understand
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mkc2502:
wrong answer. ∠B=60°
Answered by
110
@
2angleA = 3 angle B
A = 3B/2
3B = 6C
C = B/2
Now
A + B + C = 180° ( angle sum property of ∆ )
3B/2 + B + B/2 = 180°
=> (3B+2B+B)/2 = 180°
=> 6B / 2 = 180°
=> 6B = 180×2
=> 6B = 360°
=> B = 360/6
=> B = 60°
@:-)
2angleA = 3 angle B
A = 3B/2
3B = 6C
C = B/2
Now
A + B + C = 180° ( angle sum property of ∆ )
3B/2 + B + B/2 = 180°
=> (3B+2B+B)/2 = 180°
=> 6B / 2 = 180°
=> 6B = 180×2
=> 6B = 360°
=> B = 360/6
=> B = 60°
@:-)
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