in a triangle ABC, if 2∠A= 3∠B=6∠C then find the measure of ∠C
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Answer:
Step-by-step explanation:
let each ratio=k
∴2∠A = k⇒∠A =k/2............(1)
3∠B=k⇒∠B=k/3................(2)
6∠C=k⇒∠c=k/6....(3)
now,
∠A +∠B+∠C=180
from 1,2,3
K/2+K/3+K/6=180
3K+2K+K/6=180
K=180
NOW,∠C = K/6
∠C = 180/6
∴∠C = 30°
Thus,∠C = 30°.
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