Question

in a triangle ABC if 2 angle A = 3 angle B = 6 angle C calcuate angle A angle B angle C
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Answer 1

Heya !!

2 /_ A = 3 /_ B = 6 /_ C

Let 2 /_ A = 3 /_ B = 6 /_ C = X° . Then,

/_ A = (X/2)° , /_B = (X/3)° and /_ C = (X/6)°

Therefore,

X/2 + X/3 + X/6 = 180

3X + 2X + X = 1080

6X = 1080

X = 180

Therefore,

/_ A = X/2 = 180°/2 = 90°

/_ B = X/3 = 180°/3 = 60°

And,

/_ C = X/6 = 180°/6 = 30°.

Answer 2

$\huge \star \mathfrak \red{Answer!!}$

According to the condition in the △ABC, 2∠A=3∠B=6∠C

⇒∠A=3∠C and, ∠B=2∠C

Sum of interior angles of the triangle is 180o

Hence ∠A+∠B+∠C=180o

⇒3∠C+2∠C+∠C=180o

⇒∠C=30o

∴∠A=90°,∠B=60°,∠C=30°

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