Question

In a triangle ABC, if 2<A = 3<B = 6<C, calculate <A,<B, and <C.​

Answer 1

Answer:

${ \large \sf \: Let \: all \: the \: angles \: be x.} \\ \\ \sf \: ∠A= \frac{x}{2}</p><p> \sf \: x,∠B= \frac{x}{3},∠C= \frac{x}{6} \\{ \large \sf \:so,}\: \: \sf\frac{x}{2} + \frac{x}{3} + \frac{x}{6} = 180° \large \sf \:    [sum \: of \: \\ \sf \: all \: the \: angles \: of \: triangle \: is  \: 180°]\\ \sf \frac{6x + 4x + 2x}{12} = 180° \\ \sf\frac{12x}{12} = 180° \\ \sf \: x = 180° \\ \sf \: ∠A= \frac{x}{2} = \frac{180°}{2} = 90° \\ \sf \: ∠B= \frac{x}{2} = \frac{180°}{3} = 60° \\ \sf \: ∠C= \frac{x}{6} = \frac{180°}{6} =30°$