In a triangle ABC if 2angle A = 3angle B. = 6 angle C calculate angleA B and C
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HEY BUDDY..!!!
HERE'S THE ANSWER...
_______________________
▶️ There is a trick to solve this kind of questions
✔️ [ let the given data equal to a constant , say k ]
⏺️ 2 A = 3 B = 6 C = K
___________________
⏺️ K = 2A
=> A = K / 2
⏺️ K = 3 B
=> B = K / 3
⏺️ K = 6 C
=> C = K / 6
_________________
▶️ Now using Angle Sum Property ( A.S.M. ) , i.e
✔️ A + B + C = 180°
⏺️ Now by putting value
=> A + B + C = 180°
=> K / 2 + K / 3 + K / 6 = 180°
⏺️ As L.C.M is 6
=> ( 3 K + 2 K + K ) / 6 = 180°
=> 6 K / 6 = 180°
=> K = 180°
▶️ Now by putting the value of K
✔️ A = K / 2 = 180 / 2 = [ 90° ]
✔️ B = K / 3 = 180 / 3 = [ 60° ]
✔️ C = K / 6 = 180 / 6 = [ 30° ]
HOPE HELPED..
JAI HIND..
:-)
HERE'S THE ANSWER...
_______________________
▶️ There is a trick to solve this kind of questions
✔️ [ let the given data equal to a constant , say k ]
⏺️ 2 A = 3 B = 6 C = K
___________________
⏺️ K = 2A
=> A = K / 2
⏺️ K = 3 B
=> B = K / 3
⏺️ K = 6 C
=> C = K / 6
_________________
▶️ Now using Angle Sum Property ( A.S.M. ) , i.e
✔️ A + B + C = 180°
⏺️ Now by putting value
=> A + B + C = 180°
=> K / 2 + K / 3 + K / 6 = 180°
⏺️ As L.C.M is 6
=> ( 3 K + 2 K + K ) / 6 = 180°
=> 6 K / 6 = 180°
=> K = 180°
▶️ Now by putting the value of K
✔️ A = K / 2 = 180 / 2 = [ 90° ]
✔️ B = K / 3 = 180 / 3 = [ 60° ]
✔️ C = K / 6 = 180 / 6 = [ 30° ]
HOPE HELPED..
JAI HIND..
:-)
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