Question

In a triangle ABC if 2angle A=3angleB=6angleC then calculate the measure of angle A angle B and angleC

Answer 1

[tex]2A=3B; B= \frac{2A}{3} \\ \\2A=6C; C= \frac{2A}{6} \\ \\180=A+B+C=A+\frac{2A}{3}+\frac{2A}{6} =2A \\ \\ A= \frac{180}{2} =90 \\ \\ B= \frac{2A}{3}= \frac{2*90}{3}=60 \\ \\C= \frac{2A}{6}= \frac{2*90}{6}=30[/tex]

Draw: triancal.esy.es/?A=90º&B=60º

Answer 2

Answer:2A=3B;B=2A/3

2A=6C;C=2A/6

180=A+B+C=A+2A/3+2A/6=2A

A=180/2 =90

B= 2A/3 =2×90/3 =60

C=2A/6 =2×90/3 =30

Step-by-step explanation: