Question

in a triangle ABC, if 3/_A = 4/_B = /_6C, calculate the angles:: ( /_ = angle )​

Answer 1

Answer:

∠A= 80° , ∠B = 60° and ∠C = 40° are the three angles.

Step-by-step explanation:

sum of all 3 angles in a triangle is 180°

∠A +∠B + ∠C = 180°

let 3∠A = 4∠B = 6∠C = x

so, ∠A = x/3, ∠B = x/4 , ∠C = x/6

then    $\frac{x}{3} + \frac{x}{4} + \frac{x}{6} = 180^{0}$

2x + 3x + 4x = 180° * 12

9x = 180° * 12

x = 240°

∴ ∠A = x/3 = 240/3 = 80°

∴ ∠B = x/4 = 240/4 = 60°

∴ ∠C = x/6 = 240/6 = 40°