In a triangle ABC, if 3angleA=4angleC=6angleC calculate the angles
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i think this will help you to solve the problems
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ayusman1:
very very thanks
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A+B+C=180
A+(3/4)A+A/2=180
(4A+3A+2A)/4=180
9A/4=180
A=20*4
A=80
so B=(3/4)*A=60
C=A/2=40
HENCE A=80,B=60,C=40
A+(3/4)A+A/2=180
(4A+3A+2A)/4=180
9A/4=180
A=20*4
A=80
so B=(3/4)*A=60
C=A/2=40
HENCE A=80,B=60,C=40
very very thanks
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