In a triangle abc,if a=60degree,then[a+b+c][b+c-a]
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Step-by-step explanation:
Given: In a triangle ABC, A=60°
to find: [a+b+c] and [b+c-a]
Solution:
from triangle ABC,
A + B + C = 180°..............(i)
=> 60° + B + C = 180° [given that A=60°]
=> B + C = 120°.....................(ii)
Now,
(A + B + C) = 180° [from equation (i)]
And,
(B + C – A) = ( 120° – A )
[taking the B+C value from (ii)]
= 120° – 60° [given that A=60°]
= 60°
Answer: [a+b+c]= 180° and [b+c-a]= 60°
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