In a triangle ΔABC if ∠A+∠B=108° and ∠B +∠C=130° find ∠A , ∠B , ∠C
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Answer:
Step-by-step explanation:
A+B=108-----(1)
B+C=130------(2)
add (1) and
(2)
A+B+B+C=108+130
A+B+C+B=238
180+B=238 [since A+B+C=180]
B =238-180
B=58
substitute B =58 in (1) u will get A and
in(2) get C
A=50
C=72
B=58
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