In a triangle ABC, if a÷b=2÷√3 find the value of angle A and B
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Answer:
Let all the angles be x.
∠A=
2
x
,∠B=
3
x
,∠C=
6
x
So,
2
x
+
3
x
+
6
x
=180° [sum of all the angles of triangle is 180°]
12
6x+4x+2x
=180°
12
12x
=180°
x=180°
∠A=
2
x
=
2
180°
=90°
∠B=
2
x
=
3
180°
=60°
∠C=
6
x
=
6
180°
=30°
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