in a triangle ABC if (A+B) is equal to 90degree then the value of COSc is
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if A+B is 90degrees,then other angle is c=90degrees. And COS=COS90=0
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Given in ABC, B = 90o .This given A + C = 180o - 90o = 90o ......(1).Now, sin A.cos C + cos A.sin C = sin (A + C) = sin (90o) = 1 . More
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