Question

In a triangle abc , if ab= 3 cm and ac= 4 cm , then bc will be what

Answer 1

Question :-

In a right angle triangle ∆ ABC , if AB is 3 cm and AC is 4 cm then find side BC .

Answer :-

→ Side BC = 5 cm

To Find :-

→ Side BC

Formula used :-

Here we will use Pythagoras theorem

$\green{ \boxed{ \red{ \star}}} \sf{ \: {(hypt.)}^{2} = {(perpend.)}^{2} + {(base)}^{2} }$

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Solution :-

According to the question,

→ AB = 3 cm ( base)

→ AC = 4 cm ( perpendicular)

→ BC = ? ( hypotenuse)

Now substitute these values in the given formula

$\blue{ \boxed{ \red{\rightarrow}}} \: \: \sf{ {(BC)}^{2} = {(AC)}^{2} + {(AB)}^{2} } \\ \\ \boxed{ \green{\rightarrow}}\: \: \sf{ {(BC)}^{2} = {4}^{2} + {3}^{2} } \\ \\ \green{\boxed{ \pink{\rightarrow}}} \: \: \sf{ BC = \sqrt{16 + 9} } \\ \\ \red{\boxed{ \orange{ \rightarrow}}} \: \sf{ \: BC = \sqrt{5} } \\ \\ \boxed{ \blue{ \rightarrow }}\: \: \: \sf{ BC \: = 5 \: cm}$

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