In a triangle ABC , If AB = 8 cm , BC = 5 cm and CA = 9 cm , then the greatest angle is
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Greatest angle in ΔABC is ∠B and about 84.26° where AB = 8 cm , BC = 5 cm and CA = 9 cm
Given:
- ΔABC
- AB = 8 cm
- BC = 5 cm
- CA = 9 cm
To Find:
- The Greatest angle in the triangle
Solution:
- Angle opposite to largest sides is greatest in a given Triangle
Step 1:
Compare given sides of triangle
9 > 8 > 5
Hence
CA > AB > BC
Step 2:
Check the angle opposite to greatest side CA
Angle B is opposite to CA
Hence Angle B is greatest
Additional Info:
Find Measure of angle B using cosine rule
CA² = AB² + BC² - 2AB.BC cos∠B
9² = 8² + 5² - 2(8)(5)cos∠B
=> 81 = 64 + 25 - 80cos∠B
=> -8 = -80cos∠B
=> cos∠B = 1/10
=> ∠B ≈ 84.26°
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