In a triangle ABC if AB= AC and angle B=65° find angle C and angle A
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Answered by
43
angle C will be 65° as opp. angle of equal side are equal.
and by angle some property.
A + B + C = 180°
2× 65° + A = 180°
A = 180° - 130
A = 50°
and by angle some property.
A + B + C = 180°
2× 65° + A = 180°
A = 180° - 130
A = 50°
Answered by
3
Given:
- AB = AC
- ∠B = 65°
To Find:
- The value of ∠C and ∠A.
Solution:
We can say that the triangle ABC is an isosceles triangle as AB = BC.
This implies ∠C = ∠B {AB= BC}
The value of ∠B = 65° {given}
∴ ∠C = 65°
∠A+∠B+∠C = 180° {Sum of all the angles of trianhle = 180°}
On substiting the values of ∠B and ∠C in the above equation we get,
⇒ ∠A + 65° + 65° = 180° {adding the terms in LHS}
⇒ ∠A + 130° = 180°
⇒ ∠A = 180°-130° {subtrcating the terms}
⇒ ∠A = 50°
∴ The value of ∠C and ∠A is 65° and 50° respectively.
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