Question

in a triangle abc if ac is greater than ab and bisector of angle a meets bc at d then angle abd is which angle​

Answer 1

Answer:

∠ADB < ∠ADC

Step-by-step explanation:

In ΔABC, AC>AB

∴ ∠B > ∠C  [∵ ∠B is opposite to the greater side AC]

Now between ΔABD and ΔACD:

∠BAD = ∠CAD  [∵ AD is the bisector of ∠A]

∠ABD > ∠ACD  [∵ ∠B > ∠C in ΔABC]

∴ ∠ADB < ∠ADC  [∵ Sum of the three angles of ΔABD

                              = Sum of the three angles of ΔACD = 180°]