Question

In a triangle ABC if AD is bisector of Angle BAC which meets BC at point D such that BD=CD then which of the following is not true? a)AD Perpendicular To BC b) ∆ABD=∆ACD c)∆ABC is an isosceles triangle d)∆ABC is an equilateral triangle​

Answer 1

Answer:

GIVEN: BD/DC = AB/AC

TO PROVE: < BAD = < CAD

CONSTRUCTION: Extend BA to E, such that AE = AC .

PROOF: Since AE = AC

Hence < AEC = < ACE …

Since, BD/ CD = AB/AC ( given)

But , AC = AE

=> BD/CD= AB/ AE

=> AD // EC ( As intercepts on transversals BC & BE are proportional..)

So, < CEA = < DAB ( consecutive interior angles formed by // lines) …… (1)

< ECA = < CAD (alternate interior angles...AD// EC ) …….. (2)

But < CEA = < ECA

Therefore, < DAB= < CAD ( bu 1 & 2 )

Answer 2

Step-by-step explanation:

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