In a triangle ABC if angle 3a = angle 4b = 6c find the angles
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Hey dear!
Here is yr answer.....
Given, ΔABC
In which 3a = 4b = 6c
sum of all angles in a triangle = 180°
3a+4b+6c = 180
3a+3a+3a = 180
9a = 180
a = 180/9
a = 20
= 3a
= 3(20)
= 60
3a = 4b = 6c = 60
Hope it hlpz...
Here is yr answer.....
Given, ΔABC
In which 3a = 4b = 6c
sum of all angles in a triangle = 180°
3a+4b+6c = 180
3a+3a+3a = 180
9a = 180
a = 180/9
a = 20
= 3a
= 3(20)
= 60
3a = 4b = 6c = 60
Hope it hlpz...
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