Question

In a triangle abc, if angle a = 72 , angle b = 48 and c = 9 cm then is

Answer 1

Given :  in ΔABC   ∠A=72° , ∠B = 48°  , c  = 9 cm

To Find : remaining angle and sides

Solution:

Sum of angles of triangle = 180°

=> ∠A + ∠B + ∠C  = 180°

=> 72° + 48°  +  ∠C  = 180°

=>   ∠C = 60°

Using sine rule

a/SinA  = b/sinB   = c/SinC

=> a/Sin72°   = b/Sin48°  = 9/Sin60°

=> a = 9 * Sin72° /Sin60° =  9.884  cm

=> b = 9 * Sin48° /Sin60° =  9.884  cm

a = 9.884  cm

b = 7.723  cm

∠C = 60°

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