Question

In a Triangle ABC, If Angle A = 72 Degree and angle B = 63 Degree, Find Angle C.

Answer 1

Answer:

Here,

Angle A = 72 ⁰

Angle B = 63⁰

Therefore A/Q

angle A + angle B + angle C = 180 ⁰[angle sum property]

=>72⁰+63⁰+ angle C = 180 ⁰

=>Angle C=180⁰-135= 45⁰

Answer 2

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\tt In\: a \:\triangle \:ABC, \:If \angle A = {72}^{\circ}\: and \:\angle B = {63}^{\circ}, \\\tt Find\: \angle C.$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

• $\sf \bf ABC\: is \:a\: triangle$
• $\sf \bf \angle A = {72}^{\circ}$
• $\sf \bf \angle B = {63}^{\circ}$

$\sf \bf {\boxed {\mathbb {TO\:FIND}}}$

• $\sf \bf Find\:\angle C$

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

${\underbrace {\overbrace {\color {orange} {\bf By\: using\: angle\: sum \:property\: of\: triangle}}}}$

$\sf \bf \implies \angle A+\angle B+\angle C={180}^{\circ}$

$\sf \bf \implies {72}^{\circ} +{63}^{\circ}+\angle C={180}^{\circ}$

$\sf \bf \implies {135}^{\circ}+\angle C={180}^{\circ}$

$\sf \bf \implies \angle C={180}^{\circ} - {135}^{\circ}$

$\implies{\boxed {\boxed {\color {aqua} {\sf \bf \angle C ={45}^{\circ}}}}}$

${\underbrace {\color {red} {\underline {\color {red} {\overline {\color {red} {\sf \therefore The\:angle \:C\:is\:{45}^{\circ}}}}}}}}$

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

_____________________________________________

$\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

${\color {green} {\sf Identities}}$

$\sf \bf {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}$

$\sf \bf {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$

$\sf \bf (a+b) (a-b) ={a}^{2}-{b}^{2}$