In a triangle abc if angle a+ angle b =75° and angle b + angle c=130°,then find angle b
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a+b=75
b+c=130
Triangle =180
180-75=105 =c
180-130=50 =a
(105+50)-180=25 =b
Hence;
a+b=50+25=75
b+c=25+105=130
PROVED
b+c=130
Triangle =180
180-75=105 =c
180-130=50 =a
(105+50)-180=25 =b
Hence;
a+b=50+25=75
b+c=25+105=130
PROVED
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