in a triangle abc if angle a- b=40 and angle b-c =10 degree find the measures of angle a b and c
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Hi ,
a , b , c are angles of a triangle.
a - b = 40
a = 40 + b -----( 1 )
b - c = 10
c = b - 10 ------( 2 )
We know that ,
a + b + c = 180°
( 40 + b ) + b + ( b - 10 ) = 180°
[ From ( 1 ) and ( 2 ) ]
3b + 30 = 180°
3b = 180 - 30
3b = 150
b = 150/3 = 50°
Put b value in ( 1 ) & ( 2 )
a = 40 + 50= 90°
c = b - 10 = 50 - 10 = 40 °
Therefore ,
a = 90° , b = 50° , c = 40°
I hope this helps you.
:)
a , b , c are angles of a triangle.
a - b = 40
a = 40 + b -----( 1 )
b - c = 10
c = b - 10 ------( 2 )
We know that ,
a + b + c = 180°
( 40 + b ) + b + ( b - 10 ) = 180°
[ From ( 1 ) and ( 2 ) ]
3b + 30 = 180°
3b = 180 - 30
3b = 150
b = 150/3 = 50°
Put b value in ( 1 ) & ( 2 )
a = 40 + 50= 90°
c = b - 10 = 50 - 10 = 40 °
Therefore ,
a = 90° , b = 50° , c = 40°
I hope this helps you.
:)
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