in a triangle ABC , if angle ABC=90° and AB=1/2AC ,then prove angle BAC =60°.
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In triangle ABC , given that
Angle ABC=90° , AB=1/2AC
SO,
LET AC=X
AB=X/2
X+X/2=90°
2X+X/2=90°
3X=90*2
3X=180°
X=180°/3=60°
hence proofed tht angle BAC=60°
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