in a triangle ABC if BC=AC and angle C=80°,find the value of angle B
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AC=BC
Therefore Angle A=Angle B
Now we know that
Angle A+AngleB+Angle C=180°
since Angle A=Angle B
Substituting Angle A by Angle B we get
Angle B+Angle B+Angle C= 180°
2(AngleB)+80°=180° (Given Angle C=80°)
Angle B=180-80/2
Angle B=50°
Hope this helps
Therefore Angle A=Angle B
Now we know that
Angle A+AngleB+Angle C=180°
since Angle A=Angle B
Substituting Angle A by Angle B we get
Angle B+Angle B+Angle C= 180°
2(AngleB)+80°=180° (Given Angle C=80°)
Angle B=180-80/2
Angle B=50°
Hope this helps
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