In a triangle ABC, if BC = BA, ∠C = 80° then ∠A is equal to: *
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BC=AB
⇒∠A=∠C (As angles opposite to equal side are equal)
let thte angles be x each.
Now by angle sum property
∠A+∠B+∠C=180
∘
⇒x+80
∘
+x=180
∘
⇒2x=180
∘
−80
∘
⇒2x=100
∘
⇒x=50
∘
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