Math, asked by skmdfaizanallihabibi, 4 months ago

in a triangle ABC,if bsinC+csinB=2 then bsinC is

Answers

Answered by Anonymous

0

Answer:

bSinC + cSinB = 2

bSinC = 2 - cSinB

Answered by ommprakashdeo466

0

Answer:

1

Step-by-step explanation:

Given bcosC+csinB=2. eq 1

We know that

bsinC = csinB

=>bsinC - csinB=0. eq 2

Adding equation 1 and 2

We Get

2bsinC=2

=>bsinC=1

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