Question

In a triangle ABC ,if C=60,then prove that a/b+c +. b/c+a =1​

Answer 1

Step-by-step explanation:

Given In a triangle ABC ,if C = 60,then prove that a/b+c +. b/c+a =1

• We have a / b + c + b / c + a
•         Sp a(c + a) + b(b + c) / (b + c) (c + a)
•         So ac + a^2 + b^2 + bc / bc + c^2 + ab + ac --------1
• So we have Cos c = a^2 + b^2 – c^2 / 2ab
•                Or Cos 60 = a^2 + b^2 – c^2 / 2ab
•                         ½ = a^2 + b^2 – c^2 / 2ab
•                        Or a^2 + b^2 – c^2 = ab
•                       Or a^2 + b^2 = ab + c^2
•    Substituting this in eqn 1 we get
•                          ac + ab + c^2 + bc / ac + ab + c^2 + bc
•                                       = 1 (proved)

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https://brainly.in/question/6031851

https://brainly.in/question/21339464

Answer 2

Answer:

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