In a triangle ABC if CB = AB and angle B = 100°, find the value of angle A
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80degree...
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Answer:
In triangle ABC, BC=AB and angle B= 80, then angle A = 50
Solution:
Given that in triangle ABC, BC = AB which means ABC is an isosceles triangle.
We know the sum of angles in a triangle is 180°. Since it is an isosceles triangle the measure of two angles will be same. Let ∠A = x and ∠c = x
We know,
Sum of all angles = 180°
x+x+80° = 180°
2x= 180°-80°
2x=100°
x= \frac{100}{2}2100 = 50
Thus the measure of ∠A = 50°
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