Question

in a triangle ABC if cot A/2 cotB/2 =c, cotB/2cotC/2=a and cotC/2cotA/2=b then 1/s-a+1/s-b+1/s-c is
a)-1
b)0
c)1
d)2​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer ⤵️

ANSWER

By applying this equation

△

s(s−a)

:

△

s(s−b)

:

△

s(s−c)

= 1:4:15

(s−a):(s−b):(s−c)=1:4:15

now, let s−a=k , s−b=4k , s−c=15k

s−a+s−b=8k=c,

s−b+s−c=19k=a,

s−a+s−c=16k=b

now ratio of sides are a:b:c=19:16:8

now finding cosA because of a is largest side

A=120 °