Question

in a triangle ABC,if DE is parallel to BC,AD/DE=4/5 and AC =15cm , then the find length of AE

Answer 1

Answer:

Given: A D B D ADBD = 3 4 34 and AC = 15 cm [As DE ∥ BC] Required to find AE. By using Thales Theorem, [As DE ∥ BC] A D B D ADBD = A E C E AECE Let, AE = x, then CE = 15 - x. ⇒ 3 4 34 = x ( 15 – x ) x(15–x) 45 – 3x = 4x -3x – 4x = – 45 7x = 45 x = 45 7 457 x = 6.43 cm ∴ AE = 6.43 cmRead more on Sarthaks.com - https://www.sarthaks.com/633922/in-abc-and-are-points-the-sides-ab-and-ac-respectively-such-that-de-bc-if-ad-db-and-ac-15-cm-find