In a triangle ABC, if <A - <B=33 degree and <B - <C=18 degree,then <B= ?
A) 45 degree
B) 35 degree
C) 55 degree
D) 180 degree
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Answer:Sum of all angles of a triangle is 180°.
Answer:Sum of all angles of a triangle is 180°./A – /B = 33 (given)
Answer:Sum of all angles of a triangle is 180°./A – /B = 33 (given)/B – /C = 18 (given)
Answer:Sum of all angles of a triangle is 180°./A – /B = 33 (given)/B – /C = 18 (given)To find,
Answer:Sum of all angles of a triangle is 180°./A – /B = 33 (given)/B – /C = 18 (given)To find,/B = ??
Answer:Sum of all angles of a triangle is 180°./A – /B = 33 (given)/B – /C = 18 (given)To find,/B = ??step 1:
Answer:Sum of all angles of a triangle is 180°./A – /B = 33 (given)/B – /C = 18 (given)To find,/B = ??step 1:/A = 33 + /B ➜ equation 1
Answer:Sum of all angles of a triangle is 180°./A – /B = 33 (given)/B – /C = 18 (given)To find,/B = ??step 1:/A = 33 + /B ➜ equation 1/C = 18 + /B ➜ equation 2
➜ equation 2step 2:
➜ equation 2step 2:/A + /B + /C = 180°
+ /C = 180°☞ 33 + /B + /B + /B – 18 = 180°
18 = 180°☞ 3/B = 180 – 33 + 18°
18°☞ 3/B = 180 – 15°
☞ 3/B = 165°
☞ /B = 165/3°
☞ /B = 55°
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