In a triangle ABC, If tan A/2=5/6
and tan C/2=2/5,then show that a,b,c in are in A.P.
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Answer:
TanA/2.tan C/2=1/3
3[Delta ^2] /s^2 (s-a) (s-c) =1
3[s-b]/=s
2s=3b
a+b+c=3b
a+c=2b
Therefore a, b, c are in A. P.
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