Question

In a triangle ABC, in which /_A =90,AB=4cm and bc= 5 cm , the perimeter of triangle ABC is

Answer 1

Given:-

In a △ ABC, in which ∠A = 90, ∠AB = 4cm and ∠BC = 5cm, the Perimeter of △ ABC is?

To Find:-

We should have to make the sum by using Area of the Triangle. Area of the Triangle is $\sf\ \frac{1}{2}$ × base × Height.

Solution:-

Given △ABC,

• ∠A = 90°
• ∠AB = 4cm.
• ∠BC = 5cm.

$\sf\ Area \: of \: Triangle = \frac{1}{2} × base × Height$

${\Large\leadsto}\sf\ \frac{1}{2} \: \times \: 4 \: \times \: 5$

(2 and 4 cancelled by 2)

${\Large\leadsto}\sf\ \: 1 \: \times \: 2 \: \: \times \: 5$

${\Large\leadsto} \: \: {\Large{\boxed{\red{\sf{10 \: cm.}}}}}$

∴ʜᴇɴᴄᴇ, ᴛʜᴇ ᴘᴇʀɪᴍᴇᴛᴇʀ ᴏғ △ᴀʙᴄ ɪs 10ᴄᴍ.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {\LARGE{\boxed{\boxed{\boxed{\boxed{\mathfrak{\green{Vijay}}}}}}}}$

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \huge\bf\: BE$

$\: \: \: \: \: \: \: \: \: \: \: \: \bf\huge\red{B}\huge\green{R}\huge\pink{A}\huge\blue{I}\huge\purple{N}\huge\orange{LY}$