in a triangle ABC is a isoseles triangle with angle A 90 show that BCsquare = 2ABsquare
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hence proved BC²=2AB²
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given AB=AC and angle A= 90
by pythagoras theorem
BC^2=AB^2+AC^2
BC^2=AB^2+AB^2 (AB = AC)
BC^2 = 2AB^2
hence proved
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