Math, asked by Rt2005FromKT, 1 month ago

In a Triangle ABC, let a, b, c be the lengths of sides opposite to the angles A,B,C respectively and 2s = a + b+ c.
If s - a/4 = s - b/3 = s - c/2 and area in circle of triangle ABC is 8π/3. Then,

A. Area of Triangle ABC is 6√6.
B. The Radius of circumcircle of Triangle is 35√6/6
C. SinA/2sinB/2sinC/2 = 4/35
D. Sin^2 (A + B/2) = 3/5

Answers

Answered by sanjeetsrijan
0

Step-by-step explanation:

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