In a triangle ABC mazor of angle A + major of angle B =125 DEGREE.mazor A +major angle C =113 degree .so find the three angles
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Given:
∠A+∠B = 125°
∠A+∠C = 113°.
To find:
The measure of the angles of the triangle.
Solution:
1) Triangle is the polygon which have three sides, three vertices and three angles.
2) Sum of all the angles of the triangle is 180°.
∠A+∠B+∠C = 180°-------------------(A)
3) Add the equations given in the questions.
- ∠A+∠B = 125°
- ∠A+∠C = 113°
=> 2∠A+∠B+∠C = 238°
Now subtract the equation A from the above equation then we get,
- 2∠A+∠B+∠C - ( ∠A+∠B+∠C)= 238°-180°
- ∠A = 58°
∠A+∠B = 125°
- 58°+∠B = 125°
- ∠B=125°- 58°
- ∠B = 67°
∠A+∠C = 113°
- 58°+∠C = 113°
- ∠C = 113°-58°
- ∠C= 57°
The measures of the angles of the triangles are ∠A = 58°,∠B = 67° and ∠C= 57°.
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