In a triangle ABC median ad is produced to x such that AD=DX .prove that ABXC is parallelogram. can we write that BD =DC (median) AD =DX (given) since the diagonals bisect each other ABXC is a parallelogram
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BD = DC (D is the midpoint of BC)
AD = DX(given)
Therefore the diagonals bisect each other , hence it is a parallelogram .
AD = DX(given)
Therefore the diagonals bisect each other , hence it is a parallelogram .
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yes . u r right.
In triangle ABC, AD is median.
Therefore, BD=DC....eqn1
Also,AD=DX(Given)....eqn2
Now, in quad. ABXC,
AD=DX and BD=DC (Frm 1 & 2)
Therefore, ABXC is parallelogram.(A quad. is a parallelogram if its diagonals bisect each other.)
In triangle ABC, AD is median.
Therefore, BD=DC....eqn1
Also,AD=DX(Given)....eqn2
Now, in quad. ABXC,
AD=DX and BD=DC (Frm 1 & 2)
Therefore, ABXC is parallelogram.(A quad. is a parallelogram if its diagonals bisect each other.)
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