In a triangle abc, medians ad and ce are drawn. If , and , then the area of the triangle abc is equal to
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k = 1/12 , Median ad and ce of triangle abc intersect in m.The mid point of ae is n.If the area of mne is k times the area of triangle abc
Step-by-step explanation:
The three medians together divide a triangle into six equal parts,
=> Area of Δ AME = (1/6) Area of ΔABC
N is mid point of AE
=> Area of Δ MNE = (1/2) Area of Δ AME
=> Area of Δ MNE = (1/2) (1/6) Area of ΔABC
=> Area of Δ MNE = (1/12) Area of ΔABC
Area of Δ MNE = = k (Area of ΔABC)
=> k = 1/12
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