Question

in a triangle abc, mn is parallel to ac and it divides triangle ABC in 2 parts of equal area. find MB/AB
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Answer 1

Answer:

√2

Step-by-step explanation:

in ΔABC and ΔAMN

segment MN ║ BC

∠AMN=∠ABC (corresponding angle)

∠ANM=∠ACB (corresponding angle)

∠A si common

so ΔABC≅ΔAMN (CPCT)

given that 2*(area of ΔAMN )= area of ΔABC

so,

AM=√AREA OF ABC/AREA OF AMN

AM/MB= √2/1

AM/MB= √2

HOPE IT HELPS..