in a triangle ABC right angle at ab is equal to 5 AC is equal to 12 BC is equal to 13 find Sin B cos c and 10 b
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sin A = (Opposite side of the Angle A) / (Hypotenuse of the triangle)
Cos C = (Adjacent side of the Angle C) / (Hypotenuse of the triangle)
Hope it helps you. please mark as brainliest ty:)
Cos C = (Adjacent side of the Angle C) / (Hypotenuse of the triangle)
Hope it helps you. please mark as brainliest ty:)
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