Question

in a triangle Abc right angle at b Ab=24cm bc=7cm determine sin A, cos A

Answer 1

correct answer is this

Answer 2

In right ∆ABC,
By Pythagoras Theorem,
(Hypotenuse)^2 = (Perpendicular)^2 + (Base)^2
(AC)^2 = (7)^2 + (24)^2
(AC)^2 = 49 + 576
(AC)^2 = 625
AC = √625
AC = 25cm

So, we have..
AB = 24cm, BC = 7cm, AC = 25cm

Now, sinA = Perpendicular/Hypotenuse = BC/AC = 7/25
cosA = Base/Hypotenuse = AB/AC = 24/25

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