Question

in a triangle ABC right angle at B, if AB =4 and BC = 3 find all six Trignometric ratios of angle A​

Answer 1

In ∆ ABC, AB = 4 cm, BC = 3, AC = ?

By using ″ Pythagoras Theorem ″ we get AC

(HYPOTENUSE)² = (SIDE)² + (SIDE)²

➡ (AC)² = (AB)² + (BC)²

➡ (AC)² = (4)² + (3)²

➡ (AC)² = 16 + 9

➡ (AC)² = 25

➡ AC = √25

➡ AC = 5

∴ AC = 5 cm.

↪ sin A = opposite/hypotenuse

➡ sin A = BC/AC

➡ sin A = 4/5

↪ cos A = adjacent/hypotenuse

➡ cos A = AB/AC

➡ cos A = 3/5

↪ tan A = opposite/adjacent

➡ tan A = BC/AB

➡ tan A = 4/3

↪ cot A = adjacent/opposite

➡ cot A = AB/BC

➡ cot A = 3/4

↪ sec A = hypotenuse/adjacent

➡ sec A = AC/AB

➡ sec A = 5/3

↪ cosec A = hypotenuse/opposite

➡ cosec A = AC/BC

➡ cosec A = 5/4

Hence, it is solved....

Step-by-step explanation:

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