In a triangle abc right angle at c .If tan A 1/√3 find the value of cos A . cos B - sin A . sin B
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Step-by-step explanation:
ABC is a right angled triangle in which
Angle C = 90°
tanA = 1/√3 = tan30°
A = 30°
angle B = 180° - ( 90°+30°)
angle B = 180° - 120° = 60°
Now ,
CosA*CosB - SinA*SinB
Cos(A+B)
Cos(30°+60°)
Cos90° = 0
Answered by
1
Step-by-step explanation:
your answer is 0 .i tjink u got the ans by my explanation
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