Question

In a triangle abc right angle at c if tan a= 1/√3 find value of sin a cosb + cos a sin b

Answer 1

Answer:

Answer is 1

Step-by-step explanation:

tan a = 1/√3

a = atan 1/√3 = 30 deg

c = 90 deg

in a triangle

a + b + c = 180

30 + b + 90 = 180

b = 180 - 120 = 60 deg

Now

sin a cosb + cos a sin b = sin (a+b) = sin (30+60) = sin (90) = 1