In a triangle ABC right angled at A, having AB - 5cm, and
BC = 12 cm, find sin B, cos C and tan B
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Step-by-step explanation:
AB= 5cm, BC = 12cm, AC =?
so by using pythagoras theorem,
AC = _/(12)2 - (5)2 = _/144 - 25 = _/119
sin B = AC/BC = _/119 / 12
cos C = AC/BC = _/119 /12
tan B = AC/AB = _/119 /5
Hope it helps u
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